Solve the system of equations. {:[-8y+9x=-5],[8y+7x=-75],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'y' as the coefficients are the same but with opposite signs in both equations.Perform operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients are opposite, which will cancel out 'y'.Add equations to eliminate variable: Add the equations to eliminate 'y'. (-8y + 9x) + (8y + 7x) = -5 + (-75) -8y + 9x + 8y + 7x = -80 9x + 7x = -80 16x = -80Solve for x: Solve for 'x'. Dividing both sides of the equation by 16 gives us x = -80 / 16. x = -5Substitute x into first equation: Substitute x = -5 into the first equation to solve for 'y'. Substitute x = -5 in -8y + 9x = -5. We get -8y + 9(-5) = -5. This simplifies to -8y - 45 = -5.Solve for y: Solve for 'y'. Add 45 to both sides of the equation to isolate the term with 'y'. -8y - 45 + 45 = -5 + 45 -8y = 40Write solution as coordinate point: Divide both sides by -8 to find the value of 'y'. y = 40 / -8 y = -5Write the solution as a coordinate point. The solution is (-5, -5).

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Solve the system of equations.

{:[-8y+9x=-5],[8y+7x=-75],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -8 y+9 x=-5 \\ 8 y+7 x=-75 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -8 y+9 x=-5 \\ 8 y+7 x=-75 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' $y$ ' as the coefficients are the same but with opposite signs in both equations.
Perform operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients are opposite, which will cancel out ' $y$ '.
Add equations to eliminate variable: Add the equations to eliminate 'y'. $(-8y + 9x) + (8y + 7x) = -5 + (-75)$ $-8y + 9x + 8y + 7x = -80$ $9x + 7x = -80$ $16x = -80$
Solve for x: Solve for 'x'. Dividing both sides of the equation by $16$ gives us $x = -\frac{80}{16}$ . $\newline$ $x = -5$
Substitute $x$ into first equation: Substitute $x = -5$ into the first equation to solve for 'y'. Substitute $x = -5$ in $-8y + 9x = -5$ . We get $-8y + 9(-5) = -5$ . This simplifies to $-8y - 45 = -5$ .
Solve for y: Solve for 'y'. Add $45$ to both sides of the equation to isolate the term with 'y'. $\newline$ $-8y - 45 + 45 = -5 + 45$ $\newline$ $-8y = 40$
Write solution as coordinate point: Divide both sides by ext{-} $8$ to find the value of 'y'. $\newline$ $y = \frac{40}{-8}$ $\newline$ $y = -5$
Write solution as coordinate point: Divide both sides by $-8$ to find the value of ' $y$ '. $\newline$ $y = \frac{40}{-8}$ $\newline$ $y = -5$ Write the solution as a coordinate point. The solution is $(-5, -5)$ .