Q. Solve the system of equations.−6y+11x=−36−4y+7x=−24x=□y=□
Write Equations: Write down the system of equations.We have the following system of equations:−6y+11x=−36−4y+7x=−24We need to find the values of x and y that satisfy both equations.
Solve for x: Solve one of the equations for one variable.Let's solve the second equation for x:−4y+7x=−247x=4y−24x=74y−24Now we have x expressed in terms of y.
Substitute x: Substitute the expression for x into the first equation.Substitute x=74y−24 into the first equation:-6y + 11\left(\frac{4y - 24}{7}\right) = -36\(\newlineNow we need to solve for \$y\).
Eliminate Fraction: Multiply both sides of the equation by \(7\) to eliminate the fraction.\(\newline\)\(7(-6y) + 11(4y - 24) = -36 \times 7\)\(\newline\)\(-42y + 44y - 264 = -252\)\(\newline\)Now we combine like terms.
Combine Terms: Combine like terms and solve for \(y\). \(\newline\)\[2y - 264 = -252\]\(\newline\)\[2y = -252 + 264\]\(\newline\)\[2y = 12\]\(\newline\)\[y = \frac{12}{2}\]\(\newline\)\[y = 6\]\(\newline\)We have found the value of \(y\).
Find \(y\): Substitute the value of \(y\) back into the expression for \(x\). \(x = \frac{4y - 24}{7}\) \(x = \frac{4(6) - 24}{7}\) \(x = \frac{24 - 24}{7}\) \(x = \frac{0}{7}\) \(x = 0\) We have found the value of \(x\).
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