Solve the system of equations. {:[-5y+3x=3],[-8y+9x=-12],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'x' by multiplying the first equation by 3 and the second equation by -1 to make the coefficients of 'x' in both equations opposites.Multiply first equation by 3: Multiply the first equation by 3 to get 9x - 15y = 9.Multiply second equation by -1: Multiply the second equation by -1 to get 8y - 9x = 12.Add equations to eliminate 'x': Add the new equations from Step 2 and Step 3 to eliminate 'x'. (9x - 15y) + (-9x + 8y) = 9 + 12 9x - 9x - 15y + 8y = 21 -7y = 21Solve for 'y': Solve for 'y'. Dividing both sides of the equation by -7 gives us y = -3.Substitute 'y' into first equation: Substitute y = -3 into the first original equation to solve for 'x'. Substitute y = -3 in -5y + 3x = 3. We get 15 + 3x = 3. Subtract 15 from both sides, we get 3x = -12. Divide by 3, we get x = -4.Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is (-4, -3).

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Solve the system of equations.

{:[-5y+3x=3],[-8y+9x=-12],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -5 y+3 x=3 \\ -8 y+9 x=-12 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -5 y+3 x=3 \\ -8 y+9 x=-12 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' extit{x}' by multiplying the first equation by $3$ and the second equation by $-1$ to make the coefficients of ' extit{x}' in both equations opposites.
Multiply first equation by $3$ : Multiply the first equation by $3$ to get $9x - 15y = 9$ .
Multiply second equation by $-1$ : Multiply the second equation by $-1$ to get $8y - 9x = 12$ .
Add equations to eliminate 'x': Add the new equations from Step $2$ and Step $3$ to eliminate 'x'. $\newline$ $(9x - 15y) + (-9x + 8y) = 9 + 12$ $\newline$ $9x - 9x - 15y + 8y = 21$ $\newline$ $-7y = 21$
Solve for 'y': Solve for 'y'. Dividing both sides of the equation by $-7$ gives us $y = -3$ .
Substitute 'y' into first equation: Substitute $y = -3$ into the first original equation to solve for 'x'. Substitute $y = -3$ in $-5y + 3x = 3$ . We get $15 + 3x = 3$ . Subtract $15$ from both sides, we get $3x = -12$ . Divide by $3$ , we get $x = -4$ .
Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is $(-4, -3)$ .