Solve the system of equations. {:[-5x+8y=0],[-7x-8y=-96],[x=◻],[y=◻]:}

Write Equations: Let's write down the system of equations: -5x + 8y = 0 -7x - 8y = -96 We need to find the values of x and y that satisfy both equations simultaneously.Eliminate y: We can add the two equations together to eliminate y. This is because the coefficients of y in both equations are opposites (8 and -8). (-5x + 8y) + (-7x - 8y) = 0 + (-96) -5x - 7x + 8y - 8y = -96 -12x = -96Solve for x: Now we can solve for x by dividing both sides of the equation by -12. -12x / -12 = -96 / -12 x = 8Substitute x: Now that we have the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation: -5x + 8y = 0 -5(8) + 8y = 0 -40 + 8y = 0Solve for y: Now we can solve for y by adding 40 to both sides of the equation and then dividing by 8. 8y = 40 y = 40 / 8 y = 5

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Solve the system of equations.

{:[-5x+8y=0],[-7x-8y=-96],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -5 x+8 y=0 \\ -7 x-8 y=-96 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -5 x+8 y=0 \\ -7 x-8 y=-96 \\ x=\square \\ y=\square \end{array}

Write Equations: Let's write down the system of equations: $\newline$ $-5x + 8y = 0$ $\newline$ $-7x - 8y = -96$ $\newline$ We need to find the values of $x$ and $y$ that satisfy both equations simultaneously.
Eliminate y: We can add the two equations together to eliminate y. This is because the coefficients of y in both equations are opposites $8$ and $-8$ . $(-5x + 8y) + (-7x - 8y) = 0 + (-96)$ $-5x - 7x + 8y - 8y = -96$ $-12x = -96$
Solve for x: Now we can solve for $x$ by dividing both sides of the equation by $-12$ . $\frac{-12x}{-12} = \frac{-96}{-12}$ $x = 8$
Substitute $x$ : Now that we have the value of $x$ , we can substitute it back into one of the original equations to solve for $y$ . Let's use the first equation: $\newline$ $-5x + 8y = 0$ $\newline$ $-5(8) + 8y = 0$ $\newline$ $-40 + 8y = 0$
Solve for y: Now we can solve for $y$ by adding $40$ to both sides of the equation and then dividing by $8$ . $8y = 40$ $y = \frac{40}{8}$ $y = 5$