Solve the system of equations. {:[-5x+13 y=-7],[5x+4y=24],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'x' as the coefficients are the opposite in both equations.Identify operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients of 'x' are opposite.Add equations to eliminate variable: Add the equations to eliminate 'x'. (-5x + 13y) + (5x + 4y) = -7 + 24 -5x + 13y + 5x + 4y = 17 13y + 4y = 17 17y = 17Solve for y: Solve for 'y'. Dividing both sides of the equation by 17 gives us y = 1.Substitute y into first equation: Substitute y = 1 into the first equation to solve for 'x'. Substitute y = 1 in -5x + 13y = -7. We get -5x + 13(1) = -7. Simplify to get -5x + 13 = -7. Subtract 13 from both sides, we get -5x = -20.Solve for x: Solve for 'x'. Dividing both sides of the equation by -5 gives us x = 4.Write solution as coordinate point: Write the solution as a coordinate point. The solution is (4, 1).

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Solve the system of equations.

{:[-5x+13 y=-7],[5x+4y=24],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -5 x+13 y=-7 \\ 5 x+4 y=24 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -5 x+13 y=-7 \\ 5 x+4 y=24 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' $x$ ' as the coefficients are the opposite in both equations.
Identify operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients of ' $x$ ' are opposite.
Add equations to eliminate variable: Add the equations to eliminate $x$ . $(-5x + 13y) + (5x + 4y) = -7 + 24$ $-5x + 13y + 5x + 4y = 17$ $13y + 4y = 17$ $17y = 17$
Solve for y: Solve for 'y'. Dividing both sides of the equation by $17$ gives us $y = 1$ .
Substitute y into first equation: Substitute $y = 1$ into the first equation to solve for ' $x$ '. Substitute $y = 1$ in $-5x + 13y = -7$ . We get $-5x + 13(1) = -7$ . Simplify to get $-5x + 13 = -7$ . Subtract $13$ from both sides, we get $-5x = -20$ .
Solve for x: Solve for ' $x$ '. Dividing both sides of the equation by $-5$ gives us $x = 4$ .
Write solution as coordinate point: Write the solution as a coordinate point. The solution is $(4, 1)$ .