Solve the system of equations. {:[-4y+7x=49],[-16 y+9x=63],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'y' by multiplying the first equation by 4 to match the coefficient of 'y' in the second equation.Multiply first equation by 4: Multiply the first equation by 4. 4(-4y + 7x) = 4(49) -16y + 28x = 196Subtract second equation to eliminate 'y': Subtract the second equation from the modified first equation to eliminate 'y'. (-16y + 28x) - (-16y + 9x) = 196 - 63 28x - 9x = 133 19x = 133Solve for 'x': Solve for 'x'. Divide both sides of the equation by 19. x = 133 / 19 x = 7Substitute x = 7 into first equation: Substitute x = 7 into the first original equation to solve for 'y'. -4y + 7(7) = 49 -4y + 49 = 49 -4y = 49 - 49 -4y = 0Solve for 'y': Solve for 'y'. Divide both sides of the equation by -4. y = 0 / -4 y = 0Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is (7, 0).

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Solve the system of equations.

{:[-4y+7x=49],[-16 y+9x=63],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -4 y+7 x=49 \\ -16 y+9 x=63 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -4 y+7 x=49 \\ -16 y+9 x=63 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' extit{y}' by multiplying the first equation by $4$ to match the coefficient of ' extit{y}' in the second equation.
Multiply first equation by $4$ : Multiply the first equation by $4$ . $\newline$ $4(-4y + 7x) = 4(49)$ $\newline$ $-16y + 28x = 196$
Subtract second equation to eliminate 'y': Subtract the second equation from the modified first equation to eliminate 'y'. $\newline$ $(-16y + 28x) - (-16y + 9x) = 196 - 63$ $\newline$ $28x - 9x = 133$ $\newline$ $19x = 133$
Solve for 'x': Solve for 'x'. Divide both sides of the equation by $19$ . $\newline$ $x = \frac{133}{19}$ $\newline$ $x = 7$
Substitute $x = 7$ into first equation: Substitute $x = 7$ into the first original equation to solve for 'y'. $\newline$ $-4y + 7(7) = 49$ $\newline$ $-4y + 49 = 49$ $\newline$ $-4y = 49 - 49$ $\newline$ $-4y = 0$
Solve for 'y': Solve for 'y'. Divide both sides of the equation by $-4$ . $\newline$ $y = \frac{0}{-4}$ $\newline$ $y = 0$
Write the solution as a coordinate point: Write the solution as a coordinate point. $\newline$ The solution is $(7, 0)$ .