Solve the system of equations. {:[-3y+5x=26],[-2y-5x=-16],[x=◻],[y=◻]:}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'x' by adding the two equations because the coefficients of 'x' are opposites.Add equations to eliminate 'x': Add the equations to eliminate 'x'. (-3y + 5x) + (-2y - 5x) = 26 - 16 -3y + 5x - 2y - 5x = 10 -5y = 10Solve for 'y': Solve for 'y'. Dividing both sides of the equation by -5 gives us y = -2.Substitute y = -2: Substitute y = -2 into the first equation to solve for 'x'. Substitute y = -2 in -3y + 5x = 26. We get 6 + 5x = 26. Subtract 6 from both sides, we get 5x = 20.Solve for 'x': Solve for 'x'. Dividing both sides of the equation by 5 gives us x = 4.Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is (4, -2).

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Solve the system of equations.

{:[-3y+5x=26],[-2y-5x=-16],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -3 y+5 x=26 \\ -2 y-5 x=-16 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -3 y+5 x=26 \\ -2 y-5 x=-16 \\ x=\square \\ y=\square \end{array}

Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate ' extit{x}' by adding the two equations because the coefficients of ' extit{x}' are opposites.
Add equations to eliminate 'x': Add the equations to eliminate 'x'. $(-3y + 5x) + (-2y - 5x) = 26 - 16$ $\newline$ $-3y + 5x - 2y - 5x = 10$ $\newline$ $-5y = 10$
Solve for 'y': Solve for 'y'. Dividing both sides of the equation by $-5$ gives us $y = -2$ .
Substitute $y = -2$ : Substitute $y = -2$ into the first equation to solve for 'x'. Substitute $y = -2$ in $-3y + 5x = 26$ . We get $6 + 5x = 26$ . Subtract $6$ from both sides, we get $5x = 20$ .
Solve for 'x': Solve for 'x'. Dividing both sides of the equation by $5$ gives us $x = 4$ .
Write the solution as a coordinate point: Write the solution as a coordinate point. The solution is $(4, -2)$ .