Solve the system of equations. {:[-3y-4x=-11],[3y-5x=-61],[x=◻],[y=◻]:}

Write Equations: Write down the system of equations. We have the following system of equations: -3y - 4x = -11 3y - 5x = -61 We need to find the values of x and y that satisfy both equations.Add to Eliminate y: Add the two equations together to eliminate y. By adding the two equations, we get: (-3y - 4x) + (3y - 5x) = -11 + (-61) The y terms cancel out, and we are left with: -4x - 5x = -11 - 61Combine Terms for x: Combine like terms and solve for x. -4x - 5x = -9x -11 - 61 = -72 So we have: -9x = -72 Now, divide both sides by -9 to solve for x: x = -72 / -9 x = 8Substitute x for y: Substitute the value of x into one of the original equations to solve for y. Let's use the first equation: -3y - 4x = -11 Substitute x = 8: -3y - 4(8) = -11 -3y - 32 = -11Isolate y Term: Add 32 to both sides to isolate the term with y. -3y - 32 + 32 = -11 + 32 -3y = 21 Now, divide both sides by -3 to solve for y: y = 21 / -3 y = -7

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Solve the system of equations.

{:[-3y-4x=-11],[3y-5x=-61],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -3 y-4 x=-11 \\ 3 y-5 x=-61 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -3 y-4 x=-11 \\ 3 y-5 x=-61 \\ x=\square \\ y=\square \end{array}

Write Equations: Write down the system of equations. $\newline$ We have the following system of equations: $\newline$ $-3y - 4x = -11$ $\newline$ $3y - 5x = -61$ $\newline$ We need to find the values of $x$ and $y$ that satisfy both equations.
Add to Eliminate y: Add the two equations together to eliminate y. $\newline$ By adding the two equations, we get: $\newline$ $(-3y - 4x) + (3y - 5x) = -11 + (-61)$ $\newline$ The y terms cancel out, and we are left with: $\newline$ $-4x - 5x = -11 - 61$
Combine Terms for x: Combine like terms and solve for x. $\newline$ $-4x - 5x = -9x$ $\newline$ $-11 - 61 = -72$ $\newline$ So we have: $\newline$ $-9x = -72$ $\newline$ Now, divide both sides by $-9$ to solve for x: $\newline$ $x = -72 / -9$ $\newline$ $x = 8$
Substitute $x$ for $y$ : Substitute the value of $x$ into one of the original equations to solve for $y$ . Let's use the first equation: $-3y - 4x = -11$ Substitute $x = 8$ : $-3y - 4(8) = -11$ $-3y - 32 = -11$
Isolate y Term: Add $32$ to both sides to isolate the term with $y$ . $\newline$ $-3y - 32 + 32 = -11 + 32$ $\newline$ $-3y = 21$ $\newline$ Now, divide both sides by $-3$ to solve for $y$ : $\newline$ $y = \frac{21}{-3}$ $\newline$ $y = -7$