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Solve the system of equations.

{:[3x+8y=15],[2x-8y=10],[x=◻],[y=◻]:}

Solve the system of equations.\newline3x+8y=152x8y=10x=y= \begin{array}{l} 3 x+8 y=15 \\ 2 x-8 y=10 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline3x+8y=152x8y=10x=y= \begin{array}{l} 3 x+8 y=15 \\ 2 x-8 y=10 \\ x=\square \\ y=\square \end{array}
  1. Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'yy' as the coefficients are opposite in both equations.
  2. Perform operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients of 'yy' are opposite.
  3. Add equations to eliminate variable: Add the equations to eliminate yy. (3x+8y)+(2x8y)=15+10(3x + 8y) + (2x - 8y) = 15 + 103x+8y+2x8y=253x + 8y + 2x - 8y = 255x=255x = 25 This gives us 5x=255x = 25.
  4. Solve for x: Solve for 'x'. Dividing both sides of the equation by 55 gives us x=5x = 5.
  5. Substitute xx into equation: Substitute x=5x = 5 into one of the original equations to solve for 'yy'. Let's use the first equation 3x+8y=153x + 8y = 15. Substitute x=5x = 5 in, we get 3(5)+8y=153(5) + 8y = 15.
  6. Solve for y: Solve for 'y'. 15+8y=1515 + 8y = 15. Subtract 1515 from both sides, we get 8y=08y = 0. Divide by 88, we get y=0y = 0.
  7. Write solution as coordinate point: Write the solution as a coordinate point. The solution is (5,0)(5, 0).

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