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Solve the system of equations. {:[-3x+2y=56],[-5x-2y=24],[x=◻],[y=◻]:}

Solve the system of equations.\newline−3x+2y=56−5x−2y=24x=□y=□ \begin{array}{l} -3 x+2 y=56 \\ -5 x-2 y=24 \\ x=\square \\ y=\square \end{array}

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Q. Solve the system of equations.\newline−3x+2y=56−5x−2y=24x=□y=□ \begin{array}{l} -3 x+2 y=56 \\ -5 x-2 y=24 \\ x=\square \\ y=\square \end{array}
  1. Eliminate y: Add the two equations to eliminate y.\newline(−3x+2y)+(−5x−2y)=56+24(-3x + 2y) + (-5x - 2y) = 56 + 24\newline−3x−5x+2y−2y=80-3x - 5x + 2y - 2y = 80\newline−8x=80-8x = 80
  2. Solve for x: Divide both sides by −8-8 to solve for x.\newlinex=80−8x = \frac{80}{-8}\newlinex=−10x = -10
  3. Substitute xx: Substitute x=−10x = -10 into the first equation to solve for yy.\newline−3(−10)+2y=56-3(-10) + 2y = 56\newline30+2y=5630 + 2y = 56
  4. Isolate 2y2y: Subtract 3030 from both sides to isolate 2y2y.\newline2y=56−302y = 56 - 30\newline2y=262y = 26
  5. Solve for y: Divide both sides by 22 to solve for y.\newliney=262y = \frac{26}{2}\newliney=13y = 13

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