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Solve the system of equations.

{:[-2x+15 y=-24],[2x+9y=24],[x=◻],[y=◻]:}

Solve the system of equations.\newline2x+15y=242x+9y=24x=y= \begin{array}{l} -2 x+15 y=-24 \\ 2 x+9 y=24 \\ x=\square \\ y=\square \end{array}

Full solution

Q. Solve the system of equations.\newline2x+15y=242x+9y=24x=y= \begin{array}{l} -2 x+15 y=-24 \\ 2 x+9 y=24 \\ x=\square \\ y=\square \end{array}
  1. Identify variable to eliminate: Identify the variable to eliminate. In this case, we can eliminate 'xx' as the coefficients are the opposite in both equations.
  2. Identify operation to eliminate variable: Identify the operation to eliminate the variable. Here, we add the equations as the coefficients are opposite.
  3. Add equations to eliminate x: Add the equations to eliminate 'x'. (2x+15y)+(2x+9y)=24+24(-2x + 15y) + (2x + 9y) = -24 + 24 \newline2x+15y+2x+9y=0-2x + 15y + 2x + 9y = 0\newline15y+9y=015y + 9y = 0\newline24y=024y = 0\newlineThis gives us 24y=024y = 0.
  4. Solve for y: Solve for 'y'. Dividing both sides of the equation by 2424 gives us y=0y = 0.
  5. Substitute y=0 y = 0 into first equation: Substitute y=0 y = 0 into the first equation to solve for 'x x '. Substitute y=0 y = 0 in 2x+15y=24 -2x + 15y = -24 . We get 2x+0=24 -2x + 0 = -24 . Simplify to get 2x=24 -2x = -24 .
  6. Solve for x: Solve for 'x'. Dividing both sides of the equation by 2-2 gives us x=12x = 12.
  7. Write solution as coordinate point: Write the solution as a coordinate point. The solution is (12,0)(12, 0).

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