Solve the system of equations. {:[-10 y+9x=-9],[10 y+5x=-5],[x=◻],[y=◻]:}

Identify operation to eliminate variable: Identify the operation to eliminate one of the variables. In this case, we can add the two equations directly to eliminate 'y' since the coefficients of 'y' are opposite.Add equations to eliminate 'y': Add the equations to eliminate 'y'. (-10y + 9x) + (10y + 5x) = -9 + (-5) -10y + 9x + 10y + 5x = -14 9x + 5x = -14 14x = -14Solve for 'x': Solve for 'x'. Divide both sides of the equation by 14 to find the value of 'x'. 14x / 14 = -14 / 14 x = -1Substitute x = -1 to solve for 'y': Substitute x = -1 into one of the original equations to solve for 'y'. We can use the second equation 10y + 5x = -5. 10y + 5(-1) = -5 10y - 5 = -5Solve for 'y': Solve for 'y'. Add 5 to both sides of the equation to isolate the term with 'y'. 10y - 5 + 5 = -5 + 5 10y = 0Write the solution as a coordinate point: Divide both sides of the equation by 10 to find the value of 'y'. 10y / 10 = 0 / 10 y = 0Write the solution as a coordinate point. The solution is (-1, 0).

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Solve the system of equations.

{:[-10 y+9x=-9],[10 y+5x=-5],[x=◻],[y=◻]:}

Solve the system of equations. $\newline$ $\begin{array}{l} -10 y+9 x=-9 \\ 10 y+5 x=-5 \\ x=\square \\ y=\square \end{array}$

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Algebra 2

Solve a system of equations using elimination

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Q. Solve the system of equations.

\newline

\begin{array}{l} -10 y+9 x=-9 \\ 10 y+5 x=-5 \\ x=\square \\ y=\square \end{array}

Identify operation to eliminate variable: Identify the operation to eliminate one of the variables. In this case, we can add the two equations directly to eliminate ' $y$ ' since the coefficients of ' $y$ ' are opposite.
Add equations to eliminate 'y': Add the equations to eliminate 'y'. $\newline$ $(-10y + 9x) + (10y + 5x) = -9 + (-5)$ $\newline$ $-10y + 9x + 10y + 5x = -14$ $\newline$ $9x + 5x = -14$ $\newline$ $14x = -14$
Solve for 'x': Solve for 'x'. Divide both sides of the equation by $14$ to find the value of 'x'. $\newline$ $\frac{14x}{14} = \frac{-14}{14}$ $\newline$ $x = -1$
Substitute $x = -1$ to solve for 'y': Substitute $x = -1$ into one of the original equations to solve for 'y'. We can use the second equation $10y + 5x = -5$ . $\newline$ $10y + 5(-1) = -5$ $\newline$ $10y - 5 = -5$
Solve for 'y': Solve for 'y'. Add $5$ to both sides of the equation to isolate the term with 'y'. $\newline$ $10y - 5 + 5 = -5 + 5$ $\newline$ $10y = 0$
Write the solution as a coordinate point: Divide both sides of the equation by $10$ to find the value of 'y'. $\newline$ $\frac{10y}{10} = \frac{0}{10}$ $\newline$ $y = 0$
Write the solution as a coordinate point: Divide both sides of the equation by $10$ to find the value of 'y'. $\newline$ $\frac{10y}{10} = \frac{0}{10}$ $\newline$ $y = 0$ Write the solution as a coordinate point. The solution is $(-1, 0)$ .