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Percent transmittance is the percent of light that passes through an object. If 780 watts per square meter 
((W)/(m^(2))) of light strike the roof of a greenhouse, and the roof has an 
85% transmittance, how many 
(W)/(m^(2)) of light pass through the roof?

Percent transmittance is the percent of light that passes through an object. If 780780 watts per square meter (Wm2) \left(\frac{\mathrm{W}}{\mathrm{m}^{2}}\right) of light strike the roof of a greenhouse, and the roof has an 85% 85 \% transmittance, how many Wm2 \frac{\mathrm{W}}{\mathrm{m}^{2}} of light pass through the roof?

Full solution

Q. Percent transmittance is the percent of light that passes through an object. If 780780 watts per square meter (Wm2) \left(\frac{\mathrm{W}}{\mathrm{m}^{2}}\right) of light strike the roof of a greenhouse, and the roof has an 85% 85 \% transmittance, how many Wm2 \frac{\mathrm{W}}{\mathrm{m}^{2}} of light pass through the roof?
  1. Identify values: Identify the given values.\newlineWe have:\newlineThe amount of light striking the roof: 780W/m2780 \, \text{W/m}^2\newlineThe percent transmittance of the roof: 85%85\%
  2. Convert to decimal: Convert the percent transmittance to a decimal.\newlineTo convert a percentage to a decimal, divide by 100100.\newline85%=85100=0.8585\% = \frac{85}{100} = 0.85
  3. Calculate light passing through: Calculate the amount of light that passes through the roof. Multiply the amount of light striking the roof by the decimal transmittance. 780W/m2×0.85=663W/m2780 \, \text{W/m}^2 \times 0.85 = 663 \, \text{W/m}^2