On Monday, Harry had 75% as many toys as Teddy did. On Tuesday, Harry acquires 32 more toys, and Teddy acquires 15% as many toys as he had on Monday. If Harry and Teddy now have the same number of toys, how many toys did Harry have on Monday?
Q. On Monday, Harry had 75% as many toys as Teddy did. On Tuesday, Harry acquires 32 more toys, and Teddy acquires 15% as many toys as he had on Monday. If Harry and Teddy now have the same number of toys, how many toys did Harry have on Monday?
Denote Variables: Let's denote the number of toys Harry had on Monday as H and the number of toys Teddy had on Monday as T. According to the problem, Harry had 75% as many toys as Teddy did on Monday. So we can write the equation:H=0.75×T
Calculate New Totals: On Tuesday, Harry acquires 32 more toys, so his new total is H+32. Teddy acquires 15% more toys. Since 15% of T is 0.15×T, Teddy's new total is T+0.15×T, which simplifies to 1.15×T.
Equation for Equal Toys: Now, we are told that after acquiring the additional toys on Tuesday, Harry and Teddy have the same number of toys. This gives us the equation:H+32=1.15×T
Substitute and Simplify: We already know from the first step that H=0.75×T. Let's substitute 0.75×T for H in the equation from the previous step:0.75×T+32=1.15×T
Solve for Teddy's Toys: Now, let's solve for T. We'll subtract 0.75×T from both sides to isolate T on one side of the equation:0.75×T+32−0.75×T=1.15×T−0.75×T32=0.40×T
Find Teddy's Toys: To find T, we divide both sides by 0.40: T=0.4032 T=80 So Teddy had 80 toys on Monday.
Find Harry's Toys: Now that we know T, we can find H by using the equation from the first step:H=0.75×TH=0.75×80H=60So Harry had 60 toys on Monday.
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