Q. Michael is \(4\) times as old as Brandon and is also \(27\) years older than Brandon.How old is Michael?
Equation 1: Michael's age in terms of Brandon's age: Let's denote Michael's age as M and Brandon's age as B. According to the problem, Michael is 4 times as old as Brandon. We can write this as an equation:M=4B
Equation 2: Michael's age in terms of Brandon's age and the age difference: The problem also states that Michael is 27 years older than Brandon. We can write this as another equation:M=B+27
System of Equations: Now we have a system of two equations with two variables:1) M=4B2) M=B+27We can solve this system by setting the two expressions for M equal to each other since they both represent Michael's age.4B=B+27
Setting the expressions for Michael's age equal: To find the value of B, we will subtract B from both sides of the equation:4B−B=B+27−B3B=27
Solving for Brandon's age: Now we divide both sides by 3 to solve for B:33B=327B=9
Substituting Brandon's age to find Michael's age: Now that we have Brandon's age, we can find Michael's age by substituting B back into one of the original equations. Let's use the second equation M=B+27:M=9+27