Q. Michael is \(3\) times as old as Brandon. \(18\) years ago, Michael was \(9\) times as old as Brandon.How old is Brandon now?
Equation 1: Michael's age: Let's denote Michael's current age as M and Brandon's current age as B. According to the problem, Michael is 3 times as old as Brandon, which gives us our first equation:M=3B
Equation 2: Michael's age 18 years ago: The problem also states that 18 years ago, Michael was 9 times as old as Brandon. We can express this with a second equation:M−18=9(B−18)
System of Equations: Now we have a system of two equations:1) M=3B2) M−18=9(B−18)We can substitute the value of M from the first equation into the second equation to solve for B.3B−18=9(B−18)
Substitution: Let's distribute the 9 on the right side of the equation:3B−18=9B−162
Simplifying the Equation: Now, we will move all terms involving B to one side and constants to the other side:3B−9B=−162+18−6B=−144
Solving for B: Divide both sides by ext{-}6 to solve for B:B=ext−6ext−144B=24
Final Answer: Brandon is 24 years old now. This is the final answer, and it answers the question prompt.
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