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Michael is 3 times as old as Brandon. 18 years ago, Michael was 9 times as old as Brandon.
How old is Brandon now?

Michael is \(3\) times as old as Brandon. \(18\) years ago, Michael was \(9\) times as old as Brandon.\newlineHow old is Brandon now?

Full solution

Q. Michael is \(3\) times as old as Brandon. \(18\) years ago, Michael was \(9\) times as old as Brandon.\newlineHow old is Brandon now?
  1. Equation 11: Michael's age: Let's denote Michael's current age as MM and Brandon's current age as BB. According to the problem, Michael is 33 times as old as Brandon, which gives us our first equation:\newlineM=3BM = 3B
  2. Equation 22: Michael's age 1818 years ago: The problem also states that 1818 years ago, Michael was 99 times as old as Brandon. We can express this with a second equation:\newlineM18=9(B18)M - 18 = 9(B - 18)
  3. System of Equations: Now we have a system of two equations:\newline11) M=3BM = 3B\newline22) M18=9(B18)M - 18 = 9(B - 18)\newlineWe can substitute the value of MM from the first equation into the second equation to solve for BB.\newline3B18=9(B18)3B - 18 = 9(B - 18)
  4. Substitution: Let's distribute the 99 on the right side of the equation:\newline3B18=9B1623B - 18 = 9B - 162
  5. Simplifying the Equation: Now, we will move all terms involving BB to one side and constants to the other side:\newline3B9B=162+183B - 9B = -162 + 18\newline6B=144-6B = -144
  6. Solving for B: Divide both sides by ext{-}66 to solve for B:\newlineB=ext144ext6 B = \frac{ ext{-}144}{ ext{-}6} \newlineB=24 B = 24
  7. Final Answer: Brandon is 2424 years old now. This is the final answer, and it answers the question prompt.

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