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If 
2A+B=9, which of the following correctly expresses 
A in terms of 
B ?
Choose 1 answer:
(A) 
A=9-2B
(B) 
A=9-B
(C) 
A=(B-9)/(2)
(D) 
A=(9-B)/(2)

If 2A+B=9 2 A+B=9 , which of the following correctly expresses A A in terms of B B ?\newlineChoose 11 answer:\newline(A) A=92B A=9-2 B \newline(B) A=9B A=9-B \newline(C) A=B92 A=\frac{B-9}{2} \newline(D) A=9B2 A=\frac{9-B}{2}

Full solution

Q. If 2A+B=9 2 A+B=9 , which of the following correctly expresses A A in terms of B B ?\newlineChoose 11 answer:\newline(A) A=92B A=9-2 B \newline(B) A=9B A=9-B \newline(C) A=B92 A=\frac{B-9}{2} \newline(D) A=9B2 A=\frac{9-B}{2}
  1. Divide by 22: Now we need to divide both sides of the equation by 22 to solve for AA.2A2=(9B)2\frac{2A}{2} = \frac{(9 - B)}{2}This simplifies to:A=(9B)2A = \frac{(9 - B)}{2}

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