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Ben is 30 years old and Daniel is 2 years old.
How many years will it take until Ben is only 3 times as old as Daniel?

Ben is \(30\) years old and Daniel is \(2\) years old.\newlineHow many years will it take until Ben is only \(3\) times as old as Daniel?

Full solution

Q. Ben is \(30\) years old and Daniel is \(2\) years old.\newlineHow many years will it take until Ben is only \(3\) times as old as Daniel?
  1. Denoting the years: Let's denote the number of years it will take for Ben to be only 33 times as old as Daniel by nn. Currently, Ben is 3030 years old and Daniel is 22 years old. After nn years, Ben will be 30+n30 + n years old and Daniel will be 2+n2 + n years old. We are looking for the value of nn when Ben's age is 33 times Daniel's age.\newlineThe equation to represent this situation is: 30+n=3(2+n)30 + n = 3(2 + n).
  2. Solving the equation: Now we will solve the equation for "n". First, distribute the 33 on the right side of the equation.\newline30+n=3×2+3×n30 + n = 3 \times 2 + 3 \times n\newline30+n=6+3n30 + n = 6 + 3n
  3. Rearranging the equation: Next, we will rearrange the equation to isolate nn on one side. We can do this by subtracting nn from both sides and also subtracting 66 from both sides.\newline30+nn6=6+3nn630 + n - n - 6 = 6 + 3n - n - 6\newline24=2n24 = 2n
  4. Dividing both sides: Now, we divide both sides by 22 to solve for nn.\newline242=2n2\frac{24}{2} = \frac{2n}{2}\newline12=n12 = n
  5. Final result: We have found that nn equals 1212. This means it will take 1212 years for Ben to be only 33 times as old as Daniel.

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