Ben is \(20\) years older than Daniel. Ben and Daniel first met two years ago. Three years ago, Ben was \(3\) times as old as Daniel.How old is Daniel now?
Q. Ben is \(20\) years older than Daniel. Ben and Daniel first met two years ago. Three years ago, Ben was \(3\) times as old as Daniel.How old is Daniel now?
Equation 1: Ben's age: Let's denote Ben's current age as B and Daniel's current age as D. According to the problem, Ben is 20 years older than Daniel, which gives us the first equation:B=D+20
Equation 2: Three years ago: The problem states that three years ago, Ben was 3 times as old as Daniel. We need to account for their ages three years ago, so we subtract 3 from their current ages:B−3=3(D−3)
System of equations: Now we have a system of two equations:1) B=D+202) B−3=3(D−3)We can substitute the value of B from the first equation into the second equation to solve for D.(D+20)−3=3(D−3)
Substituting B into equation 2: Simplify the equation: D+17=3D−9
Simplifying the equation: Now, we will solve for D by moving all terms involving D to one side and constants to the other side:17+9=3D−D26=2D
Solving for D: Divide both sides by 2 to find the value of D:226=DD=13
Checking the solution: Now that we have Daniel's current age, we can check if the information given in the problem is consistent with our solution. Three years ago, Daniel was 13−3=10 years old. According to the problem, Ben was three times as old as Daniel three years ago. So, Ben's age three years ago should be 3×10=30 years old. Since Ben is 20 years older than Daniel, his current age should be 13+20=33 years old. Checking for Ben's age three years ago: 33−3=30, which is consistent with the problem.
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