An empty pool has the capacity to hold 2700 cubic feet (ft3) of water. A particular hose fills this pool with water at a rate of 25ft3 per minute. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after 1 hour?Choose 1 answer:(A) 10%(B) 44%(C) 56%(D) 93%
Q. An empty pool has the capacity to hold 2700 cubic feet (ft3) of water. A particular hose fills this pool with water at a rate of 25ft3 per minute. If the hose is placed into the empty pool and turned on, approximately what percent of the pool will be filled with water after 1 hour?Choose 1 answer:(A) 10%(B) 44%(C) 56%(D) 93%
Calculate total water in 1 hour: Calculate the total amount of water that the hose will fill in 1 hour.Since there are 60 minutes in an hour, and the hose fills at a rate of 25 cubic feet per minute, we multiply the rate by the number of minutes in an hour.Total water filled in 1 hour = 25 ft3/minute×60 minutes= 1500 ft3
Calculate percentage filled after 1 hour: Calculate the percentage of the pool that will be filled with the water after 1 hour.We have the total capacity of the pool and the amount of water filled in 1 hour. To find the percentage, we divide the amount filled by the total capacity and then multiply by 100.Percentage filled = Pool capacityTotal water filled in 1 hour×100%= 2700 ft31500 ft3×100%
Perform division and multiplication for percentage: Perform the division and multiplication to find the percentage.Percentage filled = (27001500)×100%= 0.5556×100%= 55.56%
Round percentage to nearest whole number: Round the percentage to the nearest whole number if necessary.Since the options are in whole numbers, we round 55.56% to the nearest whole number, which is 56%.
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