A poultry farmer has been keeping track of the number of chickens at his farm over previous years. Four years ago, the number of chickens was 64 . The number increased by 50 percent each year for four years until the present day. In the future, the farmer considers the situation where the number of chickens increases at a constant rate equal to the rate of the most recent year or the situation where the number continues to increase by 50 percent per year. What is the difference in the number of chickens between these two situations two years from now? Choose 1 answer: (A) 0 (B) 189 (c) 405 (D) 11

Question

A poultry farmer has been keeping track of the number of chickens at his farm over previous years. Four years ago, the number of chickens was 64 . The number increased by 50 percent each year for four years until the present day. In the future, the farmer considers the situation where the number of chickens increases at a constant rate equal to the rate of the most recent year or the situation where the number continues to increase by 50 percent per year. What is the difference in the number of chickens between these two situations two years from now? Choose 1 answer: (A) 0 (B)  189 (c) 405 (D) 11

Bytelearn · Accepted Answer

Calculate Present Day Chickens: First, calculate the number of chickens at the present day after increasing by 50 percent each year for four years starting from 64 chickens. Year 1: 64 * 1.5 = 96 chickens Year 2: 96 * 1.5 = 144 chickens Year 3: 144 * 1.5 = 216 chickens Year 4 (Present Day): 216 * 1.5 = 324 chickensCalculate Chickens Two Years Later (Scenario 1): Next, calculate the number of chickens two years from now if the number continues to increase by 50 percent per year. Year 1 (Future): 324 * 1.5 = 486 chickens Year 2 (Future): 486 * 1.5 = 729 chickensCalculate Chickens Two Years Later (Scenario 2): Now, calculate the number of chickens two years from now if the number increases at a constant rate equal to the rate of the most recent year. The most recent increase was from 216 to 324 chickens, which is an increase of 324 - 216 = 108 chickens per year. Year 1 (Future): 324 + 108 = 432 chickens Year 2 (Future): 432 + 108 = 540 chickensFind Difference in Chickens: Finally, find the difference in the number of chickens between the two future scenarios two years from now. Difference: 729 (Scenario 1) - 540 (Scenario 2) = 189 chickens

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