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A fruit stand has to decide what to charge for their produce. They need 
$10 for 4 apples and 4 oranges. They also need 
$12 for 6 apples and 6 oranges. We put this information into a system of linear equations.
Can we find a unique price for an apple and an orange?
Choose 1 answer:
(A) Yes; they should charge 
$1.00 for an apple and 
$1.50 for an orange.
(B) Yes; they should charge 
$1.00 for an apple and 
$1.00 for an orange.
(C) No; the system has many solutions.
(D) No; the system has no solution.

A fruit stand has to decide what to charge for their produce. They need $10 \$ 10 for 44 apples and 44 oranges. They also need $12 \$ 12 for 66 apples and 66 oranges. We put this information into a system of linear equations.\newlineCan we find a unique price for an apple and an orange?\newlineChoose 11 answer:\newlineA Yes; they should charge $1.00 \$ 1.00 for an apple and $1.50 \$ 1.50 for an orange.\newlineB Yes; they should charge $1.00 \$ 1.00 for an apple and $1.00 \$ 1.00 for an orange.\newline(C) No; the system has many solutions.\newline(D) No \mathrm{No} ; the system has no solution.

Full solution

Q. A fruit stand has to decide what to charge for their produce. They need $10 \$ 10 for 44 apples and 44 oranges. They also need $12 \$ 12 for 66 apples and 66 oranges. We put this information into a system of linear equations.\newlineCan we find a unique price for an apple and an orange?\newlineChoose 11 answer:\newlineA Yes; they should charge $1.00 \$ 1.00 for an apple and $1.50 \$ 1.50 for an orange.\newlineB Yes; they should charge $1.00 \$ 1.00 for an apple and $1.00 \$ 1.00 for an orange.\newline(C) No; the system has many solutions.\newline(D) No \mathrm{No} ; the system has no solution.
  1. Translate into equations: Let's denote the price of an apple as AA and the price of an orange as OO. We can then translate the information given into two equations:\newline11. 4A+4O=($)104A + 4O = (\$)10\newline22. 6A+6O=($)126A + 6O = (\$)12
  2. Simplify equations: We can simplify both equations by dividing them by their common factors to make the coefficients smaller and the equations easier to work with:\newline11. Divide the first equation by 44: A+O=$(2.50)A + O = \$(2.50)\newline22. Divide the second equation by 66: A+O=$(2)A + O = \$(2)

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