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9=(v+4)(v+12)9=\frac{(v+4)}{(v+12)}

Full solution

Q. 9=(v+4)(v+12)9=\frac{(v+4)}{(v+12)}
  1. Multiply by (v+12)(v+12): First, we multiply both sides of the equation by (v+12)(v+12) to eliminate the denominator.\newlineThis gives us 9(v+12)=v+49(v+12) = v+4.
  2. Distribute 99 on left side: Next, we distribute the 99 on the left side of the equation.\newlineThis gives us 9v+108=v+49v + 108 = v + 4.
  3. Subtract vv terms: Then, we subtract vv from both sides of the equation to bring all the vv terms to one side.\newlineThis gives us 9vv+108=49v - v + 108 = 4.\newlineAfter simplifying, we get 8v+108=48v + 108 = 4.
  4. Isolate term with vv: Now, we subtract 108108 from both sides of the equation to isolate the term with vv. This gives us 8v=41088v = 4 - 108. After simplifying, we get 8v=1048v = -104.
  5. Divide by 88: Finally, we divide both sides of the equation by 88 to solve for vv. This gives us v=104/8v = -104 / 8. After simplifying, we get v=13v = -13.

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