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2log_(6)u-8log_(6)v

11) 2log6u8log6v 2 \log _{6} u-8 \log _{6} v

Full solution

Q. 11) 2log6u8log6v 2 \log _{6} u-8 \log _{6} v
  1. Recognize Properties: Recognize the properties of logarithms that can be applied to simplify the expression.\newlineThe properties of logarithms that are relevant here are:\newline- The Power Rule: logb(ac)=clogb(a)\log_b(a^c) = c\log_b(a)\newlineUsing this property, we can take the coefficients in front of the logarithms and turn them into exponents inside the logarithms.
  2. Apply Power Rule: Apply the Power Rule to the given expression.\newlineWe have 2log6u8log6v2\log_{6}u - 8\log_{6}v, which can be rewritten using the Power Rule as:\newlinelog6(u2)log6(v8)\log_{6}(u^2) - \log_{6}(v^8)
  3. Combine Using Quotient Rule: Combine the two logarithms into a single logarithm using the Quotient Rule.\newlineThe Quotient Rule for logarithms states that logb(a)logb(c)=logb(ac)\log_b(a) - \log_b(c) = \log_b\left(\frac{a}{c}\right).\newlineApplying this rule to our expression gives us:\newlinelog6(u2v8)\log_{6}\left(\frac{u^2}{v^8}\right)
  4. Check for Simplifications: Check for any possible simplifications of the expression inside the logarithm. In this case, there are no further simplifications that can be made to the expression u2/v8u^2/v^8.

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