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{:[-3x-4y=4],[-5x+y=2]:}
Is 
(2,10) a solution of the system?
Choose 1 answer:
(A) Yes
(B) No

3x4y=45x+y=2 \begin{array}{r} -3 x-4 y=4 \\ -5 x+y=2 \end{array} \newlineIs (2,10) (2,10) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No

Full solution

Q. 3x4y=45x+y=2 \begin{array}{r} -3 x-4 y=4 \\ -5 x+y=2 \end{array} \newlineIs (2,10) (2,10) a solution of the system?\newlineChoose 11 answer:\newline(A) Yes\newline(B) No
  1. Substitution in First Equation: To determine if the point (2,10)(2,10) is a solution to the system of equations, we need to substitute xx with 22 and yy with 1010 in both equations and check if the left-hand side equals the right-hand side.
  2. Check First Equation Result: First, let's substitute into the first equation: 3x4y=4-3x - 4y = 4. Substituting x=2x = 2 and y=10y = 10, we get 3(2)4(10)=640=46-3(2) - 4(10) = -6 - 40 = -46. Now we check if this equals 44.
  3. Conclusion: Since 46-46 does not equal 44, we can already conclude that (2,10)(2,10) is not a solution to the first equation, and therefore, it cannot be a solution to the system of equations.

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