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{[3x-4y=13],[-9x+12 y=26]:}

{3x−4y=13−9x+12y=26 \left\{\begin{array}{l}3 x-4 y=13 \\ -9 x+12 y=26\end{array}\right.

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Q. {3x−4y=13−9x+12y=26 \left\{\begin{array}{l}3 x-4 y=13 \\ -9 x+12 y=26\end{array}\right.
  1. Analyze Equations: Analyze the system of equations to determine if they are multiples of each other.\newlineThe second equation is −3-3 times the first equation. Let's check this by multiplying the first equation by −3-3.\newline−3×(3x−4y)=−3×13-3 \times (3x - 4y) = -3 \times 13\newline−9x+12y=−39-9x + 12y = -39
  2. Check Multiples: Compare the modified first equation with the second equation.\newlineThe second equation given is −9x+12y=26-9x + 12y = 26, but when we multiplied the first equation by −3-3, we got −9x+12y=−39-9x + 12y = -39. These are not the same, which means there was a math error in Step 11.

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