Solve for x: question_prompt: What are the values of x and y that satisfy the system of equations {[3x−2y=6],[x+y=−8]}? Step 1: Solve the second equation for x.x=−8−y
Substitute x in first equation: Step 2: Substitute x in the first equation with the expression found in Step 1.3(−8−y)−2y=6
Combine like terms: Step 3: Distribute the 3 and combine like terms.−24−3y−2y=6−24−5y=6
Isolate y term: Step 4: Add 24 to both sides to isolate the term with y.−5y=6+24−5y=30
Solve for y: Step 5: Divide both sides by −5 to solve for y.y=−530y=−6
Substitute y in second equation: Step 6: Substitute y=−6 back into the second equation to solve for x.x+(−6)=−8x−6=−8
Solve for x: Step 7: Add 6 to both sides to solve for x.x=−8+6x=−2
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