Q. 12t=4v−3−6t=4v+6If (t,v) is the solution to the system of equations, what is the value of t−v ?
Write System Equations: Write down the system of equations.We have the following system of equations:12t=4v−3−6t=4v+6We need to find the value of t−v.
Solve First Equation for t: Solve the first equation for t. From the first equation, we can solve for t by dividing both sides by 12: t=124v−3
Solve Second Equation for t: Solve the second equation for t.From the second equation, we can solve for t by dividing both sides by −6:t=−64v+6
Set Expressions Equal: Set the expressions for t from both equations equal to each other.Since both expressions are equal to t, we can set them equal to each other:124v−3=−64v+6
Cross-Multiply for v: Cross-multiply to solve for v. Cross-multiplying gives us: −6(4v−3)=12(4v+6)−24v+18=48v+72
Combine Like Terms: Combine like terms and solve for v. Add 24v to both sides and subtract 72 from both sides: −24v+24v+18=48v+24v+72−7218=72v Divide both sides by 72: v=7218v=41
Substitute for t: Substitute the value of v back into one of the original equations to solve for t. Let's use the first equation: 12t=4(41)−312t=1−312t=−2 Divide both sides by 12: t=12−2t=6−1
Calculate t−v: Calculate t−v. t−v=(−61)−(41) To subtract these fractions, find a common denominator, which is 12: t−v=(−122)−(123) t−v=−125
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