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Math Problems
Algebra 1
Factor quadratics with leading coefficient 1
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
x
+
5
=
5
x^{2}+x+5=5
x
2
+
x
+
5
=
5
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
4
x
−
60
=
−
3
x
−
4
x^{2}-4 x-60=-3 x-4
x
2
−
4
x
−
60
=
−
3
x
−
4
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
10
x
−
6
=
−
2
x
−
6
x^{2}-10 x-6=-2 x-6
x
2
−
10
x
−
6
=
−
2
x
−
6
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
3
x
−
5
=
−
3
x
−
1
x^{2}-3 x-5=-3 x-1
x
2
−
3
x
−
5
=
−
3
x
−
1
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
3
x
−
2
=
−
2
x^{2}-3 x-2=-2
x
2
−
3
x
−
2
=
−
2
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
2
x
+
2
=
2
x^{2}+2 x+2=2
x
2
+
2
x
+
2
=
2
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
=
−
5
x
x^{2}=-5 x
x
2
=
−
5
x
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
5
x
=
−
3
x
x^{2}-5 x=-3 x
x
2
−
5
x
=
−
3
x
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
9
x
+
3
=
−
5
x^{2}-9 x+3=-5
x
2
−
9
x
+
3
=
−
5
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
23
=
2
x^{2}-23=2
x
2
−
23
=
2
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
12
x
+
35
=
0
x^{2}-12 x+35=0
x
2
−
12
x
+
35
=
0
\newline
Answer:
x
=
x=
x
=
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Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
5
x
−
44
=
6
x^{2}-5 x-44=6
x
2
−
5
x
−
44
=
6
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
3
x
−
42
=
4
x
x^{2}+3 x-42=4 x
x
2
+
3
x
−
42
=
4
x
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
10
x
−
4
=
x
−
4
x^{2}+10 x-4=x-4
x
2
+
10
x
−
4
=
x
−
4
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
9
=
0
x^{2}-9=0
x
2
−
9
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
x
−
10
=
x
−
1
x^{2}+x-10=x-1
x
2
+
x
−
10
=
x
−
1
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
2
x
−
36
=
−
2
x
x^{2}-2 x-36=-2 x
x
2
−
2
x
−
36
=
−
2
x
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
9
x
+
1
=
1
x^{2}+9 x+1=1
x
2
+
9
x
+
1
=
1
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
6
=
−
2
x^{2}-6=-2
x
2
−
6
=
−
2
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
6
x
+
13
=
5
x^{2}-6 x+13=5
x
2
−
6
x
+
13
=
5
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
7
x
−
36
=
−
2
x
x^{2}-7 x-36=-2 x
x
2
−
7
x
−
36
=
−
2
x
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
+
2
x
−
15
=
0
x^{2}+2 x-15=0
x
2
+
2
x
−
15
=
0
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve for all values of
x
x
x
by factoring.
\newline
x
2
−
6
x
−
64
=
−
6
x
x^{2}-6 x-64=-6 x
x
2
−
6
x
−
64
=
−
6
x
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the quadratic by factoring.
\newline
x
2
−
3
x
−
77
=
−
5
x
+
3
x^{2}-3 x-77=-5 x+3
x
2
−
3
x
−
77
=
−
5
x
+
3
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the quadratic by factoring.
\newline
x
2
−
3
x
=
4
x
−
6
x^{2}-3 x=4 x-6
x
2
−
3
x
=
4
x
−
6
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the quadratic by factoring.
\newline
x
2
+
11
=
5
x
+
5
x^{2}+11=5 x+5
x
2
+
11
=
5
x
+
5
\newline
Answer:
x
=
x=
x
=
Get tutor help
Solve the quadratic by factoring.
\newline
x
2
+
22
=
−
9
x
+
4
x^{2}+22=-9 x+4
x
2
+
22
=
−
9
x
+
4
\newline
Answer:
x
=
x=
x
=
Get tutor help
Find factors:
\newline
k
2
+
9
k
+
18
k^2 + 9k + 18
k
2
+
9
k
+
18
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When solving an equation, Francesca's first step is shown below. Which property justifies Francesca's first step?
\newline
Original Equation:
\newline
5
(
x
+
5
)
=
2
5(x+5)=2
5
(
x
+
5
)
=
2
\newline
First Step:
\newline
5
x
+
25
=
2
5 x+25=2
5
x
+
25
=
2
\newline
distributive property of multiplication over addition
\newline
subtraction property of equality
\newline
commutative property of addition
\newline
associative property of multiplication
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Factor the trinomial:
\newline
5
x
2
+
12
x
+
4
5 x^{2}+12 x+4
5
x
2
+
12
x
+
4
\newline
Answer:
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Factor the trinomial:
\newline
5
x
2
+
12
x
+
7
5 x^{2}+12 x+7
5
x
2
+
12
x
+
7
\newline
Answer:
Get tutor help
Factor.
\newline
x
2
+
8
x
+
12
x^{2}+8 x+12
x
2
+
8
x
+
12
\newline
Answer:
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solve quadratic equation
6
X
2
+
7
X
+
10
6X^2+7X+10
6
X
2
+
7
X
+
10
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Factor.
\newline
k
2
+
9
k
+
18
k^2 + 9k + 18
k
2
+
9
k
+
18
\newline
______
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