Solve for all values of x by factoring. x^(2)-6=-2 Answer: x=

Isolate x^2 term: Write down the equation and add 6 to both sides to isolate the x^2 term. x^2 - 6 = -2 x^2 - 6 + 6 = -2 + 6 x^2 = 4Factor the equation: Factor the equation x^2 = 4. We recognize that 4 is a perfect square, so we can write the equation as: x^2 = 2^2 This implies that x could be either positive or negative 2, since both (2)^2 and (-2)^2 equal 4.Write down solutions for x: Write down the two possible solutions for x. x = 2 or x = -2

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Solve for all values of
x by factoring.

x^(2)-6=-2
Answer:
x=

Solve for all values of $x$ by factoring. $\newline$ $x^{2}-6=-2$ $\newline$ Answer: $x=$

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Math Problems

Algebra 1

Factor quadratics with leading coefficient 1

Full solution

Q. Solve for all values of

x

by factoring.

\newline

x^{2}-6=-2

\newline

Answer:

x=

Isolate $x^2$ term: Write down the equation and add $6$ to both sides to isolate the $x^2$ term. $\newline$ $x^2 - 6 = -2$ $\newline$ $x^2 - 6 + 6 = -2 + 6$ $\newline$ $x^2 = 4$
Factor the equation: Factor the equation $x^2 = 4$ . $\newline$ We recognize that $4$ is a perfect square, so we can write the equation as: $\newline$ $x^2 = 2^2$ $\newline$ This implies that $x$ could be either positive or negative $2$ , since both $(2)^2$ and $(-2)^2$ equal $4$ .
Write down solutions for x: Write down the two possible solutions for x. $\newline$ $x = 2$ or $x = -2$