Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Solve for all values of 
x by factoring.

x^(2)+2x-15=0
Answer: 
x=

Solve for all values of x x by factoring.\newlinex2+2x15=0 x^{2}+2 x-15=0 \newlineAnswer: x= x=

Full solution

Q. Solve for all values of x x by factoring.\newlinex2+2x15=0 x^{2}+2 x-15=0 \newlineAnswer: x= x=
  1. Identify Equation: Identify the quadratic equation to be factored.\newlineWe have the quadratic equation x2+2x15=0x^2 + 2x - 15 = 0. We need to find two numbers that multiply to give 15-15 (the constant term) and add up to 22 (the coefficient of the xx term).
  2. Find Numbers: Find two numbers that multiply to 15-15 and add up to 22. The numbers 55 and 3-3 satisfy these conditions because 5×(3)=155 \times (-3) = -15 and 5+(3)=25 + (-3) = 2.
  3. Rewrite Equation: Rewrite the quadratic equation using the two numbers found.\newlineThe equation x2+2x15=0x^2 + 2x - 15 = 0 can be rewritten as x2+5x3x15=0x^2 + 5x - 3x - 15 = 0 by splitting the middle term using the numbers 55 and 3-3.
  4. Factor by Grouping: Factor by grouping.\newlineGroup the terms to factor by common terms: (x2+5x)(3x+15)=0(x^2 + 5x) - (3x + 15) = 0.\newlineFactor out an xx from the first group and a 3-3 from the second group: x(x+5)3(x+5)=0x(x + 5) - 3(x + 5) = 0.
  5. Factor Common Factor: Factor out the common binomial factor.\newlineSince both groups contain the factor (x+5)(x + 5), factor it out: (x3)(x+5)=0(x - 3)(x + 5) = 0.
  6. Solve for x: Solve for x by setting each factor equal to zero.\newlineSet the first factor equal to zero: x3=0x - 3 = 0, which gives x=3x = 3.\newlineSet the second factor equal to zero: x+5=0x + 5 = 0, which gives x=5x = -5.