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x^(2)+(13)/(2)x+(15)/(2)=0 If x=a and x=b are the solutions to the given equation, what is the value of ab ? Choose 1 answer: (A) -15 (B) -(15)/(2) (c) (15)/(2) (D) 15

x2+132x+152=0 x^{2}+\frac{13}{2} x+\frac{15}{2}=0 \newlineIf x=a x=a and x=b x=b are the solutions to the given equation, what is the value of ab a b ?\newlineChoose 11 answer:\newline(A) −15-15\newlineB −152 -\frac{15}{2} \newline(C) 152 \frac{15}{2} \newline(D) 15 \mathbf{1 5}

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Q. x2+132x+152=0 x^{2}+\frac{13}{2} x+\frac{15}{2}=0 \newlineIf x=a x=a and x=b x=b are the solutions to the given equation, what is the value of ab a b ?\newlineChoose 11 answer:\newline(A) −15-15\newlineB −152 -\frac{15}{2} \newline(C) 152 \frac{15}{2} \newline(D) 15 \mathbf{1 5}
  1. Use Quadratic Equation Formula: We will use the fact that for a quadratic equation of the form ax2+bx+c=0ax^2 + bx + c = 0, the product of the roots is given by ca\frac{c}{a}. Here, a=1a = 1, b=132b = \frac{13}{2}, and c=152c = \frac{15}{2}.
  2. Calculate Product of Roots: We calculate the product of the roots using the formula ca\frac{c}{a}. ab=1521ab = \frac{\frac{15}{2}}{1}
  3. Simplify Expression: Simplify the expression to find the value of abab.ab=152ab = \frac{15}{2}

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