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Write the equation of the parabola that passes through the points (5,0(-5,0), (2,9(-2,9), and (3,0(3,0).\newlineWrite your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.

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Q. Write the equation of the parabola that passes through the points (5,0(-5,0), (2,9(-2,9), and (3,0(3,0).\newlineWrite your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.
  1. Identify x-intercepts: We have the points (5,0)(-5,0), (2,9)(-2,9), and (3,0)(3,0). The points where the parabola crosses the x-axis are (5,0)(-5,0) and (3,0)(3,0), which means these are the x-intercepts of the parabola. Therefore, we can identify the values of pp and qq as p=5p = -5 and q=3q = 3.
  2. Substitute pp and qq: Using the standard form of a parabola y=a(xp)(xq)y = a(x - p)(x - q), we substitute p=5p = -5 and q=3q = 3 into the equation to get y=a(x+5)(x3)y = a(x + 5)(x - 3).
  3. Find value of aa: Now we need to find the value of aa. We can use the point (2,9)(-2,9) to do this. Substituting x=2x = -2 and y=9y = 9 into the equation y=a(x+5)(x3)y = a(x + 5)(x - 3) gives us 9=a(2+5)(23)9 = a(-2 + 5)(-2 - 3).
  4. Solve for aa: Solving the equation 9=a(3)(5)9 = a(3)(-5) gives us 9=15a9 = -15a. Dividing both sides by 15-15, we get a=915a = -\frac{9}{15}, which simplifies to a=35a = -\frac{3}{5}.
  5. Write final equation: Now that we have found a=35a = -\frac{3}{5}, we can write the final equation of the parabola. Substituting a=35a = -\frac{3}{5} into y=a(x+5)(x3)y = a(x + 5)(x - 3), we get y=35(x+5)(x3)y = -\frac{3}{5}(x + 5)(x - 3).

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