What is the amplitude of g(x)=-2sin((pi)/(2)x-3)+5? units

Identify standard form: Identify the standard form of a sine function. The standard form of a sine function is y = A*sin(Bx - C) + D, where A is the amplitude, B affects the period, C is the phase shift, and D is the vertical shift.Compare given function: Compare the given function to the standard form. The given function is g(x) = -2sin((pi/2)x - 3) + 5. Here, A = -2, B = pi/2, C = 3, and D = 5.Determine amplitude: Determine the amplitude. The amplitude is the absolute value of A. In this case, A = -2, so the amplitude is |A| = |-2| = 2.Check for errors: Check for any mathematical errors. There are no mathematical errors in the previous steps.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the amplitude of

g(x)=-2sin((pi)/(2)x-3)+5?
units

What is the amplitude of $\newline$ $g(x)=-2 \sin \left(\frac{\pi}{2} x-3\right)+5 ?$ $\newline$ units

View step-by-step help

Home

Math Problems

Algebra 2

Domain and range of quadratic functions: equations

Full solution

Q. What is the amplitude of

\newline

g(x)=-2 \sin \left(\frac{\pi}{2} x-3\right)+5 ?

\newline

units

Identify standard form: Identify the standard form of a sine function. $\newline$ The standard form of a sine function is $y = A\sin(Bx - C) + D$ , where $A$ is the amplitude, $B$ affects the period, $C$ is the phase shift, and $D$ is the vertical shift.
Compare given function: Compare the given function to the standard form. $\newline$ The given function is $g(x) = -2\sin\left(\frac{\pi}{2}x - 3\right) + 5$ . Here, $A = -2$ , $B = \frac{\pi}{2}$ , $C = 3$ , and $D = 5$ .
Determine amplitude: Determine the amplitude. $\newline$ The amplitude is the absolute value of $A$ . In this case, $A = -2$ , so the amplitude is $|A| = |-2| = 2$ .
Check for errors: Check for any mathematical errors. $\newline$ There are no mathematical errors in the previous steps.