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Write the equation of the parabola that passes through the points (3,24(-3,24), (2,0(-2,0), and (3,0(3,0). Write your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.

Full solution

Q. Write the equation of the parabola that passes through the points (3,24(-3,24), (2,0(-2,0), and (3,0(3,0). Write your answer in the form y=a(xp)(xq)y = a(x - p)(x - q), where aa, pp, and qq are integers, decimals, or simplified fractions.
  1. Identify x-intercepts: We have the points (3,24)(-3,24), (2,0)(-2,0), and (3,0)(3,0). The points (2,0)(-2,0) and (3,0)(3,0) are the x-intercepts of the parabola, so they give us the values of pp and qq directly. Therefore, p=2p = -2 and q=3q = 3.
  2. Write parabola equation: Using the values of pp and qq, we can write the equation of the parabola in the form y=a(xp)(xq)y = a(x - p)(x - q). Substituting 2-2 for pp and 33 for qq, we get y=a(x+2)(x3)y = a(x + 2)(x - 3).
  3. Find value of a: Now we need to find the value of aa. We can use the point (3,24)(-3,24) to do this. Substituting 3-3 for xx and 2424 for yy into the equation y=a(x+2)(x3)y = a(x + 2)(x - 3), we get 24=a(3+2)(33)24 = a(-3 + 2)(-3 - 3).
  4. Solve for aa: Solving the equation 24=a(1)(6)24 = a(-1)(-6), we find that 24=6a24 = 6a, which means that a=246=4a = \frac{24}{6} = 4.
  5. Final equation of parabola: Now that we have found a=4a = 4, we can write the final equation of the parabola. Substituting 44 for aa, 2-2 for pp, and 33 for qq into the equation y=a(xp)(xq)y = a(x - p)(x - q), we get y=4(x+2)(x3)y = 4(x + 2)(x - 3).

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