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Write
(1-10 i)^(2) in simplest
a+bi form.
Answer:

Write $(1-10 i)^{2}$ in simplest $a+b i$ form. $\newline$ Answer:

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Csc, sec, and cot of special angles

Full solution

Q. Write

(1-10 i)^{2}

in simplest

a+b i

form.

\newline

Answer:

Calculate $a^2$ : To square the complex number $(1-10i)$ , we will use the formula $(a+bi)^2 = a^2 + 2abi - b^2$ , where $a=1$ and $b=-10$ .
Calculate $2abi$ : First, we calculate $a^2$ , which is $1^2 = 1$ .
Calculate $-b^2$ : Next, we calculate $2abi$ , which is $2 \times 1 \times (-10i) = -20i$ .
Combine results: Then, we calculate $-b^2$ , which is $-(-10)^2 = -100$ .
Simplify expression: Now, we combine these results to get the squared form: $1^2 + 2 \times 1 \times (-10i) - (-10)^2 = 1 - 20i - 100$ .
Simplify expression: Now, we combine these results to get the squared form: $1^2 + 2 \times 1 \times (-10i) - (-10)^2 = 1 - 20i - 100$ . Simplify the expression to get the final result: $1 - 20i - 100 = -99 - 20i$ .

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