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Which value of 
x satisfies the equation 
(5)/(4)(x-(2)/(3))=(125)/(12) ?
8

-9

-8
9

Which value of x x satisfies the equation 54(x23)=12512 \frac{5}{4}\left(x-\frac{2}{3}\right)=\frac{125}{12} ?\newline88\newline9 -9 \newline8 -8 \newline99

Full solution

Q. Which value of x x satisfies the equation 54(x23)=12512 \frac{5}{4}\left(x-\frac{2}{3}\right)=\frac{125}{12} ?\newline88\newline9 -9 \newline8 -8 \newline99
  1. Identify equation: Identify the equation to solve.\newlineWe have the equation (54)(x23)=12512(\frac{5}{4})(x - \frac{2}{3}) = \frac{125}{12}. Our goal is to find the value of xx that satisfies this equation.
  2. Clear fractions: Clear the fraction on the left side by multiplying both sides of the equation by the reciprocal of 54\frac{5}{4}, which is 45\frac{4}{5}.\left(\frac{\(4\)}{\(5\)}\right) \times \left(\frac{\(5\)}{\(4\)}\right)(x - \frac{\(2\)}{\(3\)}) = \left(\frac{\(4\)}{\(5\)}\right) \times \left(\frac{\(125\)}{\(12\)}\right)
  3. Simplify left side: Simplify the left side of the equation.\(\newline(45)×(54)(\frac{4}{5}) \times (\frac{5}{4}) simplifies to 11, so we are left with x23x - \frac{2}{3} on the left side.\newlinex23=(45)×(12512)x - \frac{2}{3} = (\frac{4}{5}) \times (\frac{125}{12})
  4. Perform multiplication: Perform the multiplication on the right side of the equation.\newline(\frac{\(4\)}{\(5\)}) \times (\frac{\(125\)}{\(12\)}) = (\frac{\(4\) \times \(125\)}{\(5\) \times \(12\)})\(\newline= \frac{500500}{6060}\newline= \frac{5050}{66}\newline= \frac{2525}{33}\newlineSo, x - \frac{22}{33} = \frac{2525}{33}
  5. Add 23\frac{2}{3}: Add 23\frac{2}{3} to both sides of the equation to isolate xx.
    x23+23=253+23x - \frac{2}{3} + \frac{2}{3} = \frac{25}{3} + \frac{2}{3}
    x=253+23x = \frac{25}{3} + \frac{2}{3}
  6. Add fractions: Add the fractions on the right side of the equation.\newline253+23=(25+2)3\frac{25}{3} + \frac{2}{3} = \frac{(25 + 2)}{3}\newline=273= \frac{27}{3}\newlinex=273x = \frac{27}{3}
  7. Simplify fraction: Simplify the fraction on the right side to find the value of xx.273=9\frac{27}{3} = 9So, x=9x = 9

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