What is the area of the region bound by the graphs of f(x)=sqrt(x-2),g(x)=14-x, and x=2 ? Choose 1 answer: (A) (19)/(6) (B) (99)/(2) (C) (151)/(2) (D) (45)/(2)

Find Intersection Points: Find the intersection points of f(x) and g(x). Set sqrt(x-2) = 14-x. Solve for x: Solve for x: x-2 = (14-x)^2. This simplifies to x-2 = 196-28x+x^2.

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What is the area of the region bound by the graphs of
f(x)=sqrt(x-2),g(x)=14-x, and
x=2 ?
Choose 1 answer:
(A)
(19)/(6)
(B)
(99)/(2)
(C)
(151)/(2)
(D)
(45)/(2)

What is the area of the region bound by the graphs of $f(x)=\sqrt{x-2}, g(x)=14-x$ , and $x=2$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $\frac{19}{6}$ $\newline$ (B) $\frac{99}{2}$ $\newline$ (C) $\frac{151}{2}$ $\newline$ (D) $\frac{45}{2}$

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Operations with rational exponents

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Q. What is the area of the region bound by the graphs of

f(x)=\sqrt{x-2}, g(x)=14-x

, and

x=2

\newline

Choose

1

answer:

\newline

(A)

\frac{19}{6}

\newline

(B)

\frac{99}{2}

\newline

(C)

\frac{151}{2}

\newline

(D)

\frac{45}{2}

Find Intersection Points: Find the intersection points of $f(x)$ and $g(x)$ . Set $\sqrt{x-2} = 14-x$ .
Solve for x: Solve for x: $x-2 = (14-x)^2$ . This simplifies to $x-2 = 196-28x+x^2$ .