Which value of x satisfies the equation (4)/(3)(x-(1)/(4))=-(37)/(3) ? 9 -8 8 -9

Question

Which value of  x satisfies the equation  (4)/(3)(x-(1)/(4))=-(37)/(3) ? 9  -8 8  -9

Bytelearn · Accepted Answer

Isolate variable x: First, we need to isolate the variable x by getting rid of the fraction on the left side of the equation. To do this, we can multiply both sides of the equation by the reciprocal of the fraction's coefficient, which is (3/4). So we multiply both sides by (3/4) to get: (3/4) * (4/3)(x - 1/4) = (3/4) * -(37/3)Simplify left side: Now we simplify both sides of the equation. On the left side, the (3/4) and (4/3) will cancel each other out, leaving us with just x - 1/4. On the right side, we multiply the numerators and the denominators separately: (3 * -37) / (4 * 3)Simplify right side: Simplifying the right side further, we get: -111 / 12 Now the equation looks like this: x - 1/4 = -111 / 12Get x by itself: Next, we need to get x by itself. To do this, we add 1/4 to both sides of the equation to cancel out the -1/4 on the left side: x - 1/4 + 1/4 = -111 / 12 + 1/4Add fractions on right: We need to add the fractions on the right side. To do this, we need a common denominator. The least common multiple of 12 and 4 is 12, so we convert 1/4 to 3/12: x = -111 / 12 + 3 / 12Add numerators: Now we add the numerators on the right side: x = (-111 + 3) / 12 x = -108 / 12Simplify fraction: Finally, we simplify the fraction on the right side by dividing -108 by 12: x = -108 / 12 x = -9

Which value of $x$ satisfies the equation $\frac{4}{3}\left(x-\frac{1}{4}\right)=-\frac{37}{3}$ ? $\newline$ $9$ $\newline$ $-8$ $\newline$ $8$ $\newline$ $-9$

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Which value of x x x satisfies the equation 43(x−14)=−373 \frac{4}{3}\left(x-\frac{1}{4}\right)=-\frac{37}{3} 34​(x−41​)=−337​ ?\newline999\newline−8 -8 −8\newline888\newline−9 -9 −9

Which value of $x$ satisfies the equation $\frac{4}{3}\left(x-\frac{1}{4}\right)=-\frac{37}{3}$ ? $\newline$ $9$ $\newline$ $-8$ $\newline$ $8$ $\newline$ $-9$