What is the value of A when we rewrite ((6)/(17))^(9x) as A^(x) ? Choose 1 answer: (A) A=((6)/(17))^(9) (B) A=-(1)/(9) (C) A=(54)/(17) (D) A=((17)/(6))^(9)

Problem Understanding: Understand the problem. We need to express ((6)/(17))^(9x) in the form of A^(x), where A is a constant.Expression Rewrite: Rewrite the given expression. We have ((6)/(17))^(9x) and we want to write it as A^(x). To do this, we need to find a value for A such that A^(x) = ((6)/(17))^(9x).Base Identification: Identify the base of the exponent. In the expression ((6)/(17))^(9x), the base is (6/17) and the exponent is 9x. We want to find A such that A = ((6)/(17))^9.A Calculation: Calculate the value of A. A = ((6)/(17))^9Matching Choice: Match the calculated value of A with the given choices. The correct choice that matches our calculation is: (A) A=((6)/(17))^(9)

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Let’s check out your problem:

What is the value of
A when we rewrite
((6)/(17))^(9x) as
A^(x) ?
Choose 1 answer:
(A)
A=((6)/(17))^(9)
(B)
A=-(1)/(9)
(C)
A=(54)/(17)
(D)
A=((17)/(6))^(9)

What is the value of $A$ when we rewrite $\left(\frac{6}{17}\right)^{9 x}$ as $A^{x}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $A=\left(\frac{6}{17}\right)^{9}$ $\newline$ (B) $A=-\frac{1}{9}$ $\newline$ (C) $A=\frac{54}{17}$ $\newline$ (D) $A=\left(\frac{17}{6}\right)^{9}$

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Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

Q. What is the value of

A

when we rewrite

\left(\frac{6}{17}\right)^{9 x}

A^{x}

\newline

Choose

1

answer:

\newline

(A)

A=\left(\frac{6}{17}\right)^{9}

\newline

(B)

A=-\frac{1}{9}

\newline

(C)

A=\frac{54}{17}

\newline

(D)

A=\left(\frac{17}{6}\right)^{9}

Problem Understanding: Understand the problem. $\newline$ We need to express $\left(\frac{6}{17}\right)^{9x}$ in the form of $A^{x}$ , where $A$ is a constant.
Expression Rewrite: Rewrite the given expression. $\newline$ We have $\left(\frac{6}{17}\right)^{9x}$ and we want to write it as $A^{x}$ . To do this, we need to find a value for $A$ such that $A^{x} = \left(\frac{6}{17}\right)^{9x}$ .
Base Identification: Identify the base of the exponent. $\newline$ In the expression $\left(\frac{6}{17}\right)^{9x}$ , the base is $\frac{6}{17}$ and the exponent is $9x$ . We want to find $A$ such that $A = \left(\frac{6}{17}\right)^9$ .
A Calculation: Calculate the value of $A$ . $A = \left(\frac{6}{17}\right)^9$
Matching Choice: Match the calculated value of $A$ with the given choices. $\newline$ The correct choice that matches our calculation is: $\newline$ (A) $A=\left(\frac{6}{17}\right)^{9}$