What is the value of A when we rewrite 29^((x)/(2)) as A^(x) ? Choose 1 answer: (A) A=(29)/(2) (B) A=29^(2) (C) A=29^((1)/(2)) (D) A=((1)/(29))^(2)

Find Base A: To rewrite 29^((x)/(2)) as A^(x), we need to find a base A such that when raised to the power of x, it is equivalent to 29^((x)/(2)). This means we are looking for a base A that when squared (because the exponent x in A^(x) will be effectively halved when compared to 29^((x)/(2))) gives us 29.Square of A: We know that (A^(x))^2 = A^(2x). Therefore, if we want A^(x) to be equivalent to 29^((x)/(2)), we need A^2 to be equal to 29. This means A is the square root of 29.Calculate A: The square root of 29 is written as 29^((1)/(2)). Therefore, A = 29^((1)/(2)).Check Answer Choices: We can now check the answer choices to see which one matches our result: (A) A=(29)/(2) is incorrect because it represents a fraction, not a square root. (B) A=29^(2) is incorrect because it represents the square of 29, not the square root. (C) A=29^((1)/(2)) is correct because it represents the square root of 29. (D) A=((1)/(29))^(2) is incorrect because it represents the square of the reciprocal of 29, not the square root of 29.

Resources

Testimonials

Plans

Resources

Testimonials

Plans

AI tutor

Welcome to Bytelearn!

Let’s check out your problem:

What is the value of
A when we rewrite
29^((x)/(2)) as
A^(x) ?
Choose 1 answer:
(A)
A=(29)/(2)
(B)
A=29^(2)
(C)
A=29^((1)/(2))
(D)
A=((1)/(29))^(2)

What is the value of $A$ when we rewrite $29^{\frac{x}{2}}$ as $A^{x}$ ? $\newline$ Choose $1$ answer: $\newline$ (A) $A=\frac{29}{2}$ $\newline$ (B) $A=29^{2}$ $\newline$ (C) $A=29^{\frac{1}{2}}$ $\newline$ (D) $A=\left(\frac{1}{29}\right)^{2}$

View step-by-step help

Home

Math Problems

Algebra 1

Compare linear and exponential growth

Full solution

Q. What is the value of

A

when we rewrite

29^{\frac{x}{2}}

A^{x}

\newline

Choose

1

answer:

\newline

(A)

A=\frac{29}{2}

\newline

(B)

A=29^{2}

\newline

(C)

A=29^{\frac{1}{2}}

\newline

(D)

A=\left(\frac{1}{29}\right)^{2}

Find Base A: To rewrite $29^{(x/2)}$ as $A^x$ , we need to find a base $A$ such that when raised to the power of $x$ , it is equivalent to $29^{(x/2)}$ . This means we are looking for a base $A$ that when squared (because the exponent $x$ in $A^x$ will be effectively halved when compared to $29^{(x/2)}$ ) gives us $29$ .
Square of A: We know that $(A^{x})^2 = A^{2x}$ . Therefore, if we want $A^{x}$ to be equivalent to $29^{\frac{x}{2}}$ , we need $A^2$ to be equal to $29$ . This means $A$ is the square root of $29$ .
Calculate A: The square root of $29$ is written as $29^{(\frac{1}{2})}$ . Therefore, $A = 29^{(\frac{1}{2})}$ .
Check Answer Choices: We can now check the answer choices to see which one matches our result: $\newline$ (A) $A=\frac{29}{2}$ is incorrect because it represents a fraction, not a square root. $\newline$ (B) $A=29^{2}$ is incorrect because it represents the square of $29$ , not the square root. $\newline$ (C) $A=29^{\frac{1}{2}}$ is correct because it represents the square root of $29$ . $\newline$ (D) $A=\left(\frac{1}{29}\right)^{2}$ is incorrect because it represents the square of the reciprocal of $29$ , not the square root of $29$ .