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What is the value of A when we rewrite 1.44^(-1.2 x) as A^(x) ? Choose 1 answer: (A) A=(144)/(12) (B) A=1.44^(-1.2) (C) A=1.44^(1.2) (D) A=12^(24 x)

What is the value of A A when we rewrite 1.44−1.2x 1.44^{-1.2 x} as Ax A^{x} ?\newlineChoose 11 answer:\newline(A) A=14412 A=\frac{144}{12} \newline(B) A=1.44−1.2 A=1.44^{-1.2} \newline(C) A=1.441.2 A=1.44^{1.2} \newline(D) A=1224x A=12^{24 x}

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Full solution

Q. What is the value of A A when we rewrite 1.44−1.2x 1.44^{-1.2 x} as Ax A^{x} ?\newlineChoose 11 answer:\newline(A) A=14412 A=\frac{144}{12} \newline(B) A=1.44−1.2 A=1.44^{-1.2} \newline(C) A=1.441.2 A=1.44^{1.2} \newline(D) A=1224x A=12^{24 x}
  1. Understand the problem: Understand the problem.\newlineWe need to express the function 1.44−1.2x1.44^{-1.2 x} in the form of AxA^{x}, where AA is a constant.
  2. Rewrite function: Rewrite the given function in the required form.\newlineWe have 1.44(−1.2x)1.44^{(-1.2 x)} and we want it to be in the form A(x)A^{(x)}. To find AA, we need to isolate the base of the exponent such that the exponent is just xx.
  3. Identify base: Identify the base AA.\newlineSince the exponent in the given function is −1.2x-1.2x, we can equate AA to 1.441.44 raised to the power of −1.2-1.2 to get the base in terms of xx.\newlineA=1.44−1.2A = 1.44^{-1.2}
  4. Match choices: Match the expression for AA with the given choices.\newlineLooking at the choices provided, we see that choice (B) A=1.44−1.2A=1.44^{-1.2} matches our expression for AA.

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