Q. What is the range of this quadratic function?y=x2−12x+35Choices:(A)y∣y≥6(B)y∣y≥−1(C)y∣y≤−1(D)all real numbers
Find Vertex: We have the quadratic function y=x2−12x+35. To find the range, we first need to determine the vertex of the parabola. The x-coordinate of the vertex can be found using the formula x=−2ab, where a is the coefficient of x2 and b is the coefficient of x.
Calculate x-coordinate: Substitute a=1 and b=−12 into the formula x=−2ab to find the x-coordinate of the vertex.x=−2×1−12x=212x=6
Calculate y-coordinate: Now that we have the x-coordinate of the vertex, we can find the y-coordinate by substituting x=6 into the original equation y=x2−12x+35. y=(6)2−12(6)+35 y=36−72+35 y=−36+35 y=−1
Determine Parabola Direction: The vertex of the parabola is (6,−1). Since the coefficient of x2 is positive (a=1), the parabola opens upwards. This means that the vertex represents the minimum point on the graph of the quadratic function.
Find Range: Given that the parabola opens upwards and the y-coordinate of the vertex is −1, the range of the function is all y-values that are greater than or equal to −1.Range:{y∣y≥−1}
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