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Three points on the graph of the function 
f(x) are 
{(0,3),(1,9),(2,27)}. Which equation represents 
f(x) ?

f(x)=6x+3

f(x)=3(3)^(x)

f(x)=18 x-9

f(x)=x^(2)+3

Three points on the graph of the function f(x) f(x) are {(0,3),(1,9),(2,27)} \{(0,3),(1,9),(2,27)\} . Which equation represents f(x) f(x) ?\newlinef(x)=6x+3 f(x)=6 x+3 \newlinef(x)=3(3)x f(x)=3(3)^{x} \newlinef(x)=18x9 f(x)=18 x-9 \newlinef(x)=x2+3 f(x)=x^{2}+3

Full solution

Q. Three points on the graph of the function f(x) f(x) are {(0,3),(1,9),(2,27)} \{(0,3),(1,9),(2,27)\} . Which equation represents f(x) f(x) ?\newlinef(x)=6x+3 f(x)=6 x+3 \newlinef(x)=3(3)x f(x)=3(3)^{x} \newlinef(x)=18x9 f(x)=18 x-9 \newlinef(x)=x2+3 f(x)=x^{2}+3
  1. Given Points Testing: We are given three points on the graph of the function f(x)f(x): (0,3)(0,3), (1,9)(1,9), and (2,27)(2,27). To determine which equation represents f(x)f(x), we can plug these points into each of the given equations to see which one is consistent with all three points.
  2. Equation 11 Testing: First, let's test the point (0,3)(0,3) with the equation f(x)=6x+3f(x)=6x+3.\newlinef(0)=6×0+3=3f(0) = 6\times 0 + 3 = 3.\newlineThis matches the given point (0,3)(0,3), so this equation could be correct.
  3. Equation 22 Testing: Next, let's test the point (1,9)(1,9) with the equation f(x)=6x+3f(x)=6x+3. f(1)=6×1+3=9f(1) = 6\times1 + 3 = 9. This also matches the given point (1,9)(1,9), so this equation is still a candidate.
  4. Equation 33 Testing: Now, let's test the point (2,27)(2,27) with the equation f(x)=6x+3f(x)=6x+3. f(2)=6×2+3=15f(2) = 6\times2 + 3 = 15. This does not match the given point (2,27)(2,27), so f(x)=6x+3f(x)=6x+3 cannot be the correct equation.
  5. Final Equation Determination: Let's move on to the next equation, f(x)=3(3)xf(x)=3(3)^{x}, and test the point (0,3)(0,3).f(0)=3(30)=31=3f(0) = 3\cdot(3^{0}) = 3\cdot1 = 3.This matches the given point (0,3)(0,3), so this equation could be correct.
  6. Final Equation Determination: Let's move on to the next equation, f(x)=3(3)xf(x)=3(3)^{x}, and test the point (0,3)(0,3).f(0)=3(30)=31=3f(0) = 3\cdot(3^0) = 3\cdot1 = 3.This matches the given point (0,3)(0,3), so this equation could be correct.Now, let's test the point (1,9)(1,9) with the equation f(x)=3(3)xf(x)=3(3)^{x}.f(1)=3(31)=33=9f(1) = 3\cdot(3^1) = 3\cdot3 = 9.This matches the given point (1,9)(1,9), so this equation is still a candidate.
  7. Final Equation Determination: Let's move on to the next equation, f(x)=3(3)xf(x)=3(3)^{x}, and test the point (0,3)(0,3).f(0)=3(30)=31=3f(0) = 3\cdot(3^0) = 3\cdot1 = 3.This matches the given point (0,3)(0,3), so this equation could be correct.Now, let's test the point (1,9)(1,9) with the equation f(x)=3(3)xf(x)=3(3)^{x}.f(1)=3(31)=33=9f(1) = 3\cdot(3^1) = 3\cdot3 = 9.This matches the given point (1,9)(1,9), so this equation is still a candidate.Next, let's test the point (2,27)(2,27) with the equation f(x)=3(3)xf(x)=3(3)^{x}.(0,3)(0,3)00.This matches the given point (2,27)(2,27), so f(x)=3(3)xf(x)=3(3)^{x} is the correct equation.
  8. Final Equation Determination: Let's move on to the next equation, f(x)=3(3)xf(x)=3(3)^{x}, and test the point (0,3)(0,3).f(0)=3(30)=31=3f(0) = 3\cdot(3^0) = 3\cdot1 = 3.This matches the given point (0,3)(0,3), so this equation could be correct.Now, let's test the point (1,9)(1,9) with the equation f(x)=3(3)xf(x)=3(3)^{x}.f(1)=3(31)=33=9f(1) = 3\cdot(3^1) = 3\cdot3 = 9.This matches the given point (1,9)(1,9), so this equation is still a candidate.Next, let's test the point (2,27)(2,27) with the equation f(x)=3(3)xf(x)=3(3)^{x}.(0,3)(0,3)00.This matches the given point (2,27)(2,27), so f(x)=3(3)xf(x)=3(3)^{x} is the correct equation.We do not need to test the remaining equations because we have already found the equation that matches all three given points. The correct equation is f(x)=3(3)xf(x)=3(3)^{x}.

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