Q. Three points on the graph of the function f(x) are {(0,3),(1,9),(2,27)}. Which equation represents f(x) ?f(x)=6x+3f(x)=3(3)xf(x)=18x−9f(x)=x2+3
Given Points Testing: We are given three points on the graph of the function f(x): (0,3), (1,9), and (2,27). To determine which equation represents f(x), we can plug these points into each of the given equations to see which one is consistent with all three points.
Equation 1 Testing: First, let's test the point (0,3) with the equation f(x)=6x+3.f(0)=6×0+3=3.This matches the given point (0,3), so this equation could be correct.
Equation 2 Testing: Next, let's test the point (1,9) with the equation f(x)=6x+3. f(1)=6×1+3=9. This also matches the given point (1,9), so this equation is still a candidate.
Equation 3 Testing: Now, let's test the point (2,27) with the equation f(x)=6x+3. f(2)=6×2+3=15. This does not match the given point (2,27), so f(x)=6x+3 cannot be the correct equation.
Final Equation Determination: Let's move on to the next equation, f(x)=3(3)x, and test the point (0,3).f(0)=3⋅(30)=3⋅1=3.This matches the given point (0,3), so this equation could be correct.
Final Equation Determination: Let's move on to the next equation, f(x)=3(3)x, and test the point (0,3).f(0)=3⋅(30)=3⋅1=3.This matches the given point (0,3), so this equation could be correct.Now, let's test the point (1,9) with the equation f(x)=3(3)x.f(1)=3⋅(31)=3⋅3=9.This matches the given point (1,9), so this equation is still a candidate.
Final Equation Determination: Let's move on to the next equation, f(x)=3(3)x, and test the point (0,3).f(0)=3⋅(30)=3⋅1=3.This matches the given point (0,3), so this equation could be correct.Now, let's test the point (1,9) with the equation f(x)=3(3)x.f(1)=3⋅(31)=3⋅3=9.This matches the given point (1,9), so this equation is still a candidate.Next, let's test the point (2,27) with the equation f(x)=3(3)x.(0,3)0.This matches the given point (2,27), so f(x)=3(3)x is the correct equation.
Final Equation Determination: Let's move on to the next equation, f(x)=3(3)x, and test the point (0,3).f(0)=3⋅(30)=3⋅1=3.This matches the given point (0,3), so this equation could be correct.Now, let's test the point (1,9) with the equation f(x)=3(3)x.f(1)=3⋅(31)=3⋅3=9.This matches the given point (1,9), so this equation is still a candidate.Next, let's test the point (2,27) with the equation f(x)=3(3)x.(0,3)0.This matches the given point (2,27), so f(x)=3(3)x is the correct equation.We do not need to test the remaining equations because we have already found the equation that matches all three given points. The correct equation is f(x)=3(3)x.
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