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The volume of a sphere is increasing at a rate of $25 \pi$ cubic meters per hour.$\newline$At a certain instant, the volume is $\frac{32 \pi}{3}$ cubic meters.$\newline$What is the rate of change of the surface area of the sphere at that instant (in square meters per hour)?$\newline$Choose $1$ answer:$\newline$(A) $\frac{32 \pi}{9}$$\newline$(B) $25 \pi$$\newline$(C) $\frac{25}{16}$$\newline$(D) $(\sqrt[3]{25 \pi})^{2}$$\newline$The surface area of a sphere with radius $r$ is $4 \pi r^{2}$.$\newline$The volume of $a$ sphere with radius $r$ is $\frac{4}{3} \pi r^{3}$.