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The radius of a cone is increasing at a rate of $3$ centimeters per second and the height of the cone is decreasing at a rate of $4$ centimeters per second.$\newline$At a certain instant, the radius is $8$ centimeters and the height is $10$ centimeters.$\newline$What is the rate of change of the volume of the cone at that instant (in cubic centimeters per second)?$\newline$Choose $1$ answer:$\newline$(A) $-\frac{736 \pi}{3}$$\newline$(B) $-\frac{224 \pi}{3}$$\newline$(C) $\frac{736 \pi}{3}$$\newline$(D) $\frac{224 \pi}{3}$$\newline$The volume of $a$ cone with radius $r$ and height $h$ is $\pi r^{2} \frac{h}{3}$.