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The polynomial function 
f is defined as 
f(c)=(c-k)(c^(2)-4c+4) where 
k is a constant. The value 2 is a zero of 
f. What is the remainder of 
f(c) when divided by 
(c-2) ?

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The polynomial function ff is defined as f(c)=(ck)(c24c+4)f(c)=(c-k)(c^{2}-4c+4) where kk is a constant. The value 22 is a zero of ff. What is the remainder of f(c)f(c) when divided by (c2)?(c-2)?\newline

Full solution

Q. The polynomial function ff is defined as f(c)=(ck)(c24c+4)f(c)=(c-k)(c^{2}-4c+4) where kk is a constant. The value 22 is a zero of ff. What is the remainder of f(c)f(c) when divided by (c2)?(c-2)?\newline
  1. Identify Given Information: Identify the given information and the question prompt.\newlineWe are given that f(c)=(ck)(c24c+4)f(c) = (c-k)(c^2 - 4c + 4) and that 22 is a zero of ff. We need to find the remainder when f(c)f(c) is divided by (c2)(c-2).
  2. Determine Value of k: Use the fact that 22 is a zero of ff to determine the value of kk. If 22 is a zero of ff, then f(2)=0f(2) = 0. We can substitute cc with 22 in the equation f(c)=(ck)(c24c+4)f(c) = (c-k)(c^2 - 4c + 4) to find kk. ff00
  3. Apply Remainder Theorem: Simplify the equation to find kk.f(2)=(2k)(48+4)=(2k)(0)=0f(2) = (2-k)(4 - 8 + 4) = (2-k)(0) = 0Since (2k)(0)=0(2-k)(0) = 0 for any value of kk, we cannot determine kk from this equation. However, we do not need the value of kk to find the remainder when f(c)f(c) is divided by (c2)(c-2).
  4. Substitute to Find Remainder: Apply the Remainder Theorem to find the remainder.\newlineThe Remainder Theorem states that the remainder of a polynomial f(c)f(c) when divided by (ca)(c-a) is f(a)f(a). Since we want to divide f(c)f(c) by (c2)(c-2), we need to find f(2)f(2).
  5. Calculate Remainder: Substitute cc with 22 in the polynomial f(c)f(c) to find the remainder.\newlinef(2)=(2k)(2242+4)f(2) = (2-k)(2^2 - 4\cdot2 + 4)\newlineSimplify the expression.\newlinef(2)=(2k)(48+4)=(2k)(0)f(2) = (2-k)(4 - 8 + 4) = (2-k)(0)
  6. Calculate Remainder: Substitute cc with 22 in the polynomial f(c)f(c) to find the remainder.\newlinef(2)=(2k)(2242+4)f(2) = (2-k)(2^2 - 4\cdot2 + 4)\newlineSimplify the expression.\newlinef(2)=(2k)(48+4)=(2k)(0)f(2) = (2-k)(4 - 8 + 4) = (2-k)(0)Calculate the remainder.\newlinef(2)=(2k)(0)=0f(2) = (2-k)(0) = 0\newlineThe remainder of f(c)f(c) when divided by (c2)(c-2) is 00.

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