The number x is rational. Which statement about 7 + x is true? Choices: (A)7 + x is rational. (B)7 + x is irrational. (C)7 + x can be rational or irrational, depending on the value of x.

Question

The number x is rational. Which statement about 7 + x is true?   Choices: (A)7 + x is rational. (B)7 + x is irrational. (C)7 + x can be rational or irrational, depending on the value of x.

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Identify Number Nature: Identify the nature of the number 7. 7 is an integer, and all integers are rational numbers because they can be expressed as a fraction where the denominator is 1 (7/1).Sum Property of Rationals: Understand the property of the sum of two rational numbers. The sum of two rational numbers is always a rational number. This is because if you have two fractions a/b and c/d, their sum (ad + bc) / (bd) is also a fraction, which means it is a rational number.Apply Property to Numbers: Apply the property to the given numbers. Since x is given to be a rational number and 7 is also a rational number, their sum 7 + x must also be a rational number according to the property of rational numbers.Choose Correct Statement: Choose the correct statement from the given choices. Based on the previous steps, the statement that 7 + x is rational is true. Therefore, the correct choice is: (A) 7 + x is rational.

The number $x$ is rational. Which statement about $7 + x$ is true? $\newline$ Choices: $\newline$ (A) $7 + x$ is rational. $\newline$ (B) $7 + x$ is irrational. $\newline$ (C) $7 + x$ can be rational or irrational, depending on the value of $x$ .

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The number xxx is rational. Which statement about 7+x7 + x7+x is true?\newlineChoices:\newline(A)7+x7 + x7+x is rational.\newline(B)7+x7 + x7+x is irrational.\newline(C)7+x7 + x7+x can be rational or irrational, depending on the value of xxx.

The number $x$ is rational. Which statement about $7 + x$ is true? $\newline$ Choices: $\newline$ (A) $7 + x$ is rational. $\newline$ (B) $7 + x$ is irrational. $\newline$ (C) $7 + x$ can be rational or irrational, depending on the value of $x$ .