Q. 3x+4(2−y)=5x2−y=6xConsider the given system of equations. If (x,y) is the solution to the system, then what is the value of yx ?
Solve for y: Solve the first equation for y.We have the equation 3x+4(2−y)=5x.First, distribute the 4 into the parentheses: 3x+8−4y=5x.Now, isolate the y term by moving the other terms to the other side: −4y=5x−3x−8.Simplify the right side: −4y=2x−8.Divide both sides by −4 to solve for y: y=(2x−8)/−4.Simplify the right side: y=−0.5x+2.
Substitute y into the second equation: Substitute the expression for y into the second equation.We have the second equation 2−y=6x.Substitute y with the expression found in Step 1: 2−(−0.5x+2)=6x.Simplify the equation: 2+0.5x−2=6x.The 2's on the left side cancel out, leaving us with: 0.5x=6x.
Solve for x: Solve for x.We have the equation 0.5x=6x.Subtract 0.5x from both sides to get all x terms on one side: 0.5x−0.5x=6x−0.5x.This simplifies to 0=5.5x.Divide both sides by 5.5 to solve for x: 0/5.5=x.This gives us x=0.
Substitute x into the expression for y: Substitute x=0 into the expression for y. We have y=−0.5x+2. Substitute x with 0: y=−0.5(0)+2. Simplify the equation: y=0+2. This gives us y=2.
Calculate yx: Calculate the value of yx. We have x=0 and y=2. Substitute these values into the expression: yx=20. Simplify the expression: yx=0.
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