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The function 
f is defined as 
f(x)=x^(2)-1.
What is the 
x-coordinate of the point on the function's graph that is closest to the origin?
Choose all answers that apply:
A 
-(sqrt3)/(3)
B 
-(sqrt2)/(2)
c 0
D 
(sqrt3)/(3)
E 
(sqrt2)/(2)

The function f f is defined as f(x)=x21 f(x)=x^{2}-1 .\newlineWhat is the x x -coordinate of the point on the function's graph that is closest to the origin?\newlineChoose all answers that apply:\newlineA 33 -\frac{\sqrt{3}}{3} \newlineB 22 -\frac{\sqrt{2}}{2} \newlinec 00\newlineD 33 \frac{\sqrt{3}}{3} \newlineE 22 \frac{\sqrt{2}}{2}

Full solution

Q. The function f f is defined as f(x)=x21 f(x)=x^{2}-1 .\newlineWhat is the x x -coordinate of the point on the function's graph that is closest to the origin?\newlineChoose all answers that apply:\newlineA 33 -\frac{\sqrt{3}}{3} \newlineB 22 -\frac{\sqrt{2}}{2} \newlinec 00\newlineD 33 \frac{\sqrt{3}}{3} \newlineE 22 \frac{\sqrt{2}}{2}
  1. Define Function: The function is f(x)=x21f(x) = x^2 - 1. To find the point closest to the origin, we need to minimize the distance from the point (x,f(x))(x, f(x)) to the origin (0,0)(0,0).
  2. Calculate Distance Formula: The distance from a point (x,y)(x, y) to the origin is given by the formula D=x2+y2D = \sqrt{x^2 + y^2}. For the function f(x)f(x), this becomes D=x2+(x21)2D = \sqrt{x^2 + (x^2 - 1)^2}.
  3. Minimize Distance Formula: To minimize DD, we minimize D2D^2 to avoid dealing with the square root. So we minimize x2+(x21)2x^2 + (x^2 - 1)^2.
  4. Expand and Simplify: Expanding D2D^2 gives us x2+x42x2+1x^2 + x^4 - 2x^2 + 1. Simplifying, we get D2=x4x2+1D^2 = x^4 - x^2 + 1.
  5. Find Derivative: To find the minimum, we take the derivative of D2D^2 with respect to xx and set it equal to zero. So, d(D2)dx=4x32x\frac{d(D^2)}{dx} = 4x^3 - 2x.
  6. Set Derivative Equal to Zero: Setting the derivative equal to zero gives us 4x32x=04x^3 - 2x = 0. Factoring out 2x2x, we get 2x(2x21)=02x(2x^2 - 1) = 0.
  7. Solve for Solutions: Setting each factor equal to zero gives us two solutions: x=0x = 0 and 2x21=02x^2 - 1 = 0. Solving the second equation gives x=±1/2x = \pm\sqrt{1/2}.

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